80x^2-302x-36=0

Solution for 80x^2-302x-36=0 equation:

80x^2-302x-36=0

a = 80; b = -302; c = -36;
Δ = b2-4ac
Δ = -3022-4·80·(-36)
Δ = 102724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{102724}=\sqrt{4*25681}=\sqrt{4}*\sqrt{25681}=2\sqrt{25681}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-302)-2\sqrt{25681}}{2*80}=\frac{302-2\sqrt{25681}}{160}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-302)+2\sqrt{25681}}{2*80}=\frac{302+2\sqrt{25681}}{160}
$